परिमेय फलनों के समाकल की सूची
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नीचे प्रमुख परिमेय फलनों (rational functions) के समाकल (integrals) दिये गये हैं।
<math>\int (ax + b)^n dx</math> <math> = \frac{(ax + b)^{n+1}}{a(n + 1)} \qquad\mbox{(for } n\neq -1\mbox{)}\,\!</math> <math>\int\frac{1}{ax + b} dx</math> ax + b\right|</math> <math>\int x(ax + b)^n dx</math> <math> = \frac{a(n + 1)x - b}{a^2(n + 1)(n + 2)} (ax + b)^{n+1} \qquad\mbox{(for }n \not\in \{-1, -2\}\mbox{)}</math>
<math>\int\frac{x}{ax + b} dx</math> ax + b\right|</math> <math>\int\frac{x}{(ax + b)^2} dx</math> ax + b\right|</math> <math>\int\frac{x}{(ax + b)^n} dx</math> <math> = \frac{a(1 - n)x - b}{a^2(n - 1)(n - 2)(ax + b)^{n-1}} \qquad\mbox{(for } n\not\in \{1, 2\}\mbox{)}</math>
<math>\int\frac{x^2}{ax + b} dx</math> ax + b\right|\right)</math> <math>\int\frac{x^2}{(ax + b)^2} dx</math> ax + b\right| - \frac{b^2}{ax + b}\right)</math> <math>\int\frac{x^2}{(ax + b)^3} dx</math> ax + b\right| + \frac{2b}{ax + b} - \frac{b^2}{2(ax + b)^2}\right)</math> <math>\int\frac{x^2}{(ax + b)^n} dx</math> <math> = \frac{1}{a^3}\left(-\frac{(ax + b)^{3-n}}{(n-3)} + \frac{2b (a + b)^{2-n}}{(n-2)} - \frac{b^2 (ax + b)^{1-n}}{(n - 1)}\right) \qquad\mbox{(for } n\not\in \{1, 2, 3\}\mbox{)}</math>
<math>\int\frac{1}{x(ax + b)} dx</math> \frac{ax+b}{x}\right|</math> <math>\int\frac{1}{x^2(ax+b)} dx</math> \frac{ax+b}{x}\right|</math> <math>\int\frac{1}{x^2(ax+b)^2} dx</math> \frac{ax+b}{x}\right|\right)</math> <math>\int\frac{1}{x^2+a^2} dx</math> <math> = \frac{1}{a}\arctan\frac{x}{a}\,\!</math> <math>\int\frac{1}{x^2-a^2} dx = </math> - <math> -\frac{1}{a}\,\mathrm{arctanh}\frac{x}{a} = \frac{1}{2a}\ln\frac{a-x}{a+x} \qquad\mbox{(for }|x| < |a|\mbox{)}\,\!</math>
- <math> -\frac{1}{a}\,\mathrm{arccoth}\frac{x}{a} = \frac{1}{2a}\ln\frac{x-a}{x+a} \qquad\mbox{(for }|x| > |a|\mbox{)}\,\!</math>
for <math>a\neq 0:</math>
<math>\int\frac{1}{ax^2+bx+c} dx =</math> - <math> \frac{2}{\sqrt{4ac-b^2}}\arctan\frac{2ax+b}{\sqrt{4ac-b^2}} \qquad\mbox{(for }4ac-b^2>0\mbox{)}</math>
- <math> -\frac{2}{\sqrt{b^2-4ac}}\,\mathrm{arctanh}\frac{2ax+b}{\sqrt{b^2-4ac}} = \frac{1}{\sqrt{b^2-4ac}}\ln\left|\frac{2ax+b-\sqrt{b^2-4ac}}{2ax+b+\sqrt{b^2-4ac}}\right| \qquad\mbox{(for }4ac-b^2<0\mbox{)}</math>
- <math> -\frac{2}{2ax+b}\qquad\mbox{(for }4ac-b^2=0\mbox{)}</math>
<math>\int\frac{x}{ax^2+bx+c} dx</math> ax^2+bx+c\right|-\frac{b}{2a}\int\frac{dx}{ax^2+bx+c}</math>
<math>\int\frac{mx+n}{ax^2+bx+c} dx = </math> - <math>\frac{m}{2a}\ln\left|ax^2+bx+c\right|+\frac{2an-bm}{a\sqrt{4ac-b^2}}\arctan\frac{2ax+b}{\sqrt{4ac-b^2}} \qquad\mbox{(for }4ac-b^2>0\mbox{)}</math>
- <math>\frac{m}{2a}\ln\left|ax^2+bx+c\right|+\frac{2an-bm}{a\sqrt{b^2-4ac}}\,\mathrm{arctanh}\frac{2ax+b}{\sqrt{b^2-4ac}} \qquad\mbox{(for }4ac-b^2<0\mbox{)}</math>
- <math> \frac{m}{2a}\ln\left|ax^2+bx+c\right|-\frac{2an-bm}{a(2ax+b)} \,\,\,\,\,\,\,\,\,\, \qquad\mbox{(for }4ac-b^2=0\mbox{)}</math>
- <math>\int\frac{1}{(ax^2+bx+c)^n} dx= \frac{2ax+b}{(n-1)(4ac-b^2)(ax^2+bx+c)^{n-1}}+\frac{(2n-3)2a}{(n-1)(4ac-b^2)}\int\frac{1}{(ax^2+bx+c)^{n-1}} dx\,\!</math>
- <math>\int\frac{x}{(ax^2+bx+c)^n} dx= \frac{bx+2c}{(n-1)(4ac-b^2)(ax^2+bx+c)^{n-1}}-\frac{b(2n-3)}{(n-1)(4ac-b^2)}\int\frac{1}{(ax^2+bx+c)^{n-1}} dx\,\!</math>
- <math>\int\frac{1}{x(ax^2+bx+c)} dx= \frac{1}{2c}\ln\left|\frac{x^2}{ax^2+bx+c}\right|-\frac{b}{2c}\int\frac{1}{ax^2+bx+c} dx</math>
उपरोक्त समीकरणों के साथ आंशिक भिन्न में बदलकर समाकलन की विधि का प्रयोग करके किसी भी परिमेय फलन का समाकल निकाला जा सकता है
- <math>\frac{ex + f}{\left(ax^2+bx+c\right)^n}</math>
इन्हें भी देखें
- समाकल सूची (List of Integrals)